$-1675-2496$
$3xy+6x^2+3x$
$\frac{1-x^3}{x^2+1}$
$673-240$
$\int\frac{x^3+x^2+x+3}{x^4-4x+3}dx$
$\frac{18x^3+24x^2+20x+11}{6x+4}$
$\frac{dy}{dt}=tan4x$
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