$1.4+6+3-7+8-4+6$
$1+tan^2x=secx$
$25y^2-10xy+4y^2$
$25-110y^2+121y^2$
$\int\frac{1}{\left(u^2+9\right)^{\frac{3}{2}}}dx$
$4m-4\le12$
$\int\frac{800\ln\left(x+25\right)}{\left(x+25\right)^2}dx$
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