$1-\frac{sin^2x}{tan^2x}$
$\left(2x-1\right)\cdot dx+\left(3y+1\right)\cdot dy=0$
$\int\frac{1}{x\left(ln\left(x\right)\right)^6}dx$
$10a^2-14ab$
$2x+2y=24$
$\int3x^2\sec\left(2-4x^3\right)dx$
$3x+4x-5x+8x$
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