$\left(206\right)\left(0.8\right)$
$\tan\left(x\right)=3,2$
$\frac{3x}{x+2}+6x+4=\frac{12}{x^2+2x}$
$-8x+11>-5$
$xyz\:y\:xyz$
$1+x^8=a$
$\left(4-x\right)\left(4+2x\right)\left(4-x\right)$
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