$3-8n=-7n+2$
$\frac{0.4}{1.234}\frac{\left(1\:\right)}{1.234}$
$\frac{40xy^2}{2^3xy}$
$2\left(4-2x\right)+4\left(x-6\right)$
$-1+\left|8\right|$
$\lim_{x\to0}\left(\frac{\left(11+x\right)^2-121}{x}\right)$
$\lim_{x\to1}-\left(\frac{x^3+1}{x^4-1}\right)$
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