$\frac{3}{8}x^3-\frac{9}{7}x^3$
$-\frac{3}{4}xy^2\:-\frac{2}{3}xy^2\:-\frac{4}{9}xy^2$
$\frac{x^3-5x^2+3x+9}{x-1}$
$\frac{dy}{dx}=\frac{12x^3}{e^y}$
$\left(3^5\right)^{-1}$
$4y-24+36$
$\frac{1}{4}r=12$
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