$\lim_{x\to\infty}\left(\frac{\sqrt[3]{x^2+2}}{3x+1}\right)$
$\frac{d}{dx}\sqrt{4x+1}$
$\frac{x-2}{2}=\frac{3+2x}{3}$
$\left(2x^2-3y^6\right)^3$
$16x^2x+16x+4$
$18p+\left[-5p\right]$
$3\left(4x-2\right)$
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