$x+7>7$
$x\left(y\:+\:4\right)\:when\:x\:=\:-5\:and\:y\:=\:1\:$
$16x^2-40x+25=0$
$\int\frac{\ln\left(x\right)}{2x}dx$
$24a-32a^2-400$
$-\left(+3\right)-\left(-2+3\right)$
$\left(x^2+9\right)\left(\sqrt{x+8}\right)\left(8\right)$
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