$\frac{1}{2}x+4\ge3$
$3x+4x-5x+8x$
$-7-\left(1-4\right)+\left(-4\right)^2$
$\ln\left(2x^2+5x-2\right)=0$
$\frac{64m^6-1}{2m-m}$
$\lim_{x\to0}\left(\frac{5x^2}{\ln\left(cosx\right)}\right)$
$2^5.2^4$
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