$2\left(d-4\right)=d$
$\frac{4x^4-3x^2+10}{3x^3+4x}$
$\left(2x^4-x^2-6x-1\right)+\left(x^3-8x^2+4\right)-2\left(2x^4-x-2\right)$
$a^5\:a^{-3}$
$a^{12}-b^1^2$
$( 2 x - 3 ) ( 3 x - 5 )$
$\left(+3\right)-\left(-6\right)+\left(-2\right)$
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