$6^0$
$x+8=3x+4$
$x^5-5x^4+6x^3$
$8x^2y^3\cdot x^4$
$49x^{2}-8x+16$
$\frac{d}{dx}\:\:2t^{-\frac{3}{4}}$
$\sqrt{2}cos3x=-1$
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