$\ln\left(x\right)\ln\left(y\right)\frac{dx}{dy}=\frac{-1}{y}$

$y'-4y=0$

$3x-8x^2=0$

$2\ln\left(x\right)=4\ln\left(2\right)$

$\frac{15x}{3x-9}$

$2x-3<x+10$

$\frac{\sec\left(x\right)\cdot\cot\left(x\right)-\sin\left(x\right)}{\csc\left(x\right)\cdot\cos\left(x\right)}$