$\frac{b^4-1}{1+b^2}$
$\lim_{h\to0}\left(\frac{2-2cos\left(h\right)-sin^2\left(h\right)}{h}\right)$
$\left(2\sqrt{3}+4\right)\left(2\sqrt{3}-4\right)$
$x^2-11x+0=-11$
$4\left(x-2\right)\le4x-8$
$\frac{24g^3z^8}{8gz^2}$
$\sec\left(\:128\right)^2-\tan\left(\:128\right)^2$
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