$-\frac{1}{3}y^3+\frac{1}{6}y^3+6y^3$

$4cos^2\left(\pi\right)-3sin^2\left(\pi\right)$

$\frac{4}{9}a^2-\frac{2}{3}ab+\frac{1}{4}b^2$

$\frac{dy}{dx}\left(8x^4\left(x^2-3\right)^5\right)$

$-4x^2-16x-36$

$\frac{dx}{dy}=e^x$

$\frac{a^3b^2\cdot\left(ab^4\right)^{-1}a^{-4}}{ba^{-1}}$