$\left(-\frac{8}{\left(-5+3\right)}+\frac{12}{\left(-2+2\cdot4\right)}\right)$
$-8r+4s=-4$
$\left(4a^3c+5b^3d\right)^3$
$1-cosx=\frac{1}{2}$
$29\left(\left(-10\right)+1\right)$
$4x^2-8x+13$
$\left(13a-\frac{9}{11}b^3\right)\cdot\left(13a+\frac{9}{14}b^3\right)$
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