$\int\:\left(6x^2+12\right)e^{\left(x^3+6x\right)}dx$
$x^2-3x-15\ge0$
$1-13.7\left(c-2d\right)+x\left(c-2d\right)$
$\left(7a+2\right)^4$
$3+\left\{4-8-\left[5-\left(-8+2-7+5\right)-6\right]+\left(-9-7\right)+8\right\}$
$0\cdot u$
$3\left(2-5x\right)\ge18-12x$
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