$x^2+4y^2=0$
$\left(-2a^5\right)^3\left(-a^8\:y^3\right)^3$
$\:\frac{x}{2}=-16$
$6x^3-7x^2+4+4x^2-1-5y^3+x^2$
$5a\left(4ab\right)$
$\left(6x^2+\frac{5}{2}\right)^2$
$\theta\:+\:2\:=0$
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