$\int\tan^5\left(\frac{2x}{3}\right)\sec^2\left(\frac{2x}{3}\right)dx$
$-4\left(-5+3+9\right)+2\left(-9-2+15\right)$
$5y^2+6y+1$
$\left(1+x^2\right)\frac{dy}{dx}=y^2$
$2x\:over\:9\:=\:16$
$\lim_{x\to0}\frac{e^{ax}-1}{sen\left(bx\right)}$
$\frac{x^2+x-3}{x}$
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