$x^4+3x^3-10x^2$
$\frac{3x^4-2x^3-10x^2-2x-6}{x+1}$
$2^x-12=500$
$x^2+2x+11<0$
$\frac{dy}{dx}=\frac{1}{3x+c}$
$24:6+8:2-15:3+4-2:-1$
$-12=-2h+0.2\left(20-6h\right)$
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