$\int^2\left(4-6x\right)^4dx$
$\left(x^2+16\right)\left(x+4\right)\cdot5$
$\left(6a^3-6b^3\right)^2$
$16n+8+16n$
$\int\frac{8}{9x^2-36}dx$
$a^2-9a+8$
$=3yb=-6\:\:$
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