$x^2+4x-8=0$
$\int\:\frac{1}{\left(x+8\right)\cdot\left(x+9\right)}dx$
$\int\frac{\sen\left(7x\right)}{\cos\left(7x\right)}dx$
$-5p+4m-2p+m$
$3y^2+7y-6$
$\frac{4x^3y^3}{8x^5y^2}$
$\int\frac{8x^4}{\left(x^5+6\right)^7}dx$
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