$\frac{8x+16}{4x^2-16}$
$\lim_{x\to\infty}x^3\left(\frac{2}{x}-\sin\left(\frac{2}{x}\right)\right)$
$\int\frac{x^2+2x}{x}dx$
$\left(-8x^2+6\right)+\left(8x^2-3x-6\right)$
$\int_0^{\infty}x^3\cdot e^{-x^2}dx$
$7a^2=-65a-18$
$\left(n^2+4mn\right)\left(n^2+4mn\right)$
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