$\frac{1}{2}x+\frac{3}{2}=\frac{x+3}{2}$
$-7-8x-4+4x$
$\lim_{x\to3}\left(-3x^2-1\right)$
$\frac{272}{981}\left(0.9986\right)\:+\:\frac{709}{981}\left(0.9835\right)$
$\frac{2x^3-4x^2+2x}{x^2-2x+1}$
$-x^2+2x-10$
$y-6=10$
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