$\frac{x}{2}=\frac{-4}{x-9}$
$b^3-64$
$\int_1^{\infty}\left(\frac{x+2}{2x^{\frac{5}{3}}}\right)dx$
$f\left(x\right)=\left(3x^2-6\right)^3$
$\sqrt{x^2}-2x$
$44.1+12+4.8$
$x^8\left(x+3\right)^2\left(x^2+2x+4\right)=0$
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