$\left(\sqrt[4]{x+1}-1\right)\left(\sqrt[4]{x+1}+1\right)$
$\left(5-6\right)^2-2\left|3-7\right|$
$\sin2x=05$
$\sqrt[3]{19.3137}\cdot3$
$\frac{dy}{dx}=1+\sqrt{x+y}$
$4cos^2x+2sin^2x-3=cos2x$
$1-sec^2x=-tan^2x$
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