$\left(\frac{1}{6}x-3x\right)$
$8.8^2.8:8^3$
$\left(-1\right)\left(-1\right)\left(-1\right)\left(-2\right)\left(-66\right)$
$10\sin^2\left(x\right)+\cos\left(x\right)=7$
$\frac{3x^2y^2}{4yx^4}$
$5x-3>\frac{x}{3}$
$\frac{x^3+x^2+x-2}{x-1}$
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