$\frac{4}{3x}-\frac{1}{x^{2}}=\frac{5}{6x}$
$\frac{x^2-2x-8}{\left(x-2\right)\left(x+2\right)}$
$4\sin^2\left(300\right)$
$-11\:-\:\left(-41\right)$
$55-\left(-6\right)\cdot6$
$-5h\:+14-h-9$
$\left(5b+3\right)\left(7b-3\right)$
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