$dy=\left(2x-3\right)dx$
$\left(x-2b\right)^3$
$\frac{2-x}{x+3}>-2$
$\int_1^3\left(4e^x\right)dx$
$5x=x$
$8-[6-\left(-3+7\right)-6]+4$
$\lim_{x\to0}\left(\frac{1}{sin\left(t\right)cos\left(t\right)}-\frac{1}{t}\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!