$x+4+x+4+3+3$
$\frac{2x^2-4x+19}{x^2+2x+1}$
$4z^2-z^2$
$\int-2x^4e^{6x^5}dx$
$\frac{dy}{dx}=\frac{-y^2+3x^2}{2xy}$
$\frac{10a^5\cdot4a^3}{8a^{-2}}$
$5-3\:-\:-2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!