$\int_1^2\left(4x+4\right)dx$
$\frac{2x^3-x^2+2x+3}{x-2}$
$54\:+\:\left(-8\right)\left(4\right)$
$\lim_{x\to0}\left(\frac{\ln\left|x\right|}{x}\right)$
$x-5+3x-4$
$\int\frac{x^3}{\left(x^2+9\right)^{0.5}}dx$
$y'+y=\frac{1}{x}$
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