$6x^2-8x+x^2+x$
$4x^2-2y^2dx=2xydy$
$\frac{dy}{du}+0.25y=0.5e^{-0.5u}$
$f\left(x\right)=\left(x+3\right)^2\left(x+2\right)$
$+5=-3$
$y'=\frac{\left(x-1\right)\cdot\:\:y^5}{x^2\left(2y^3-y\right)}$
$\left(-3\right)\cdot414$
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