$\left(\frac{2p}{3q^2r^3}\right)^{-3}.\left(\frac{p^3r^2}{q^4}\right)^2$
$x^2\:-\:6x\:+\:5\:=\:0$
$\frac{x^3}{x-3}$
$-8x+1+12-4x-8$
$\int6x\left(x^2-4\right)^{-1}dx$
$\frac{x^2+12x+20}{x-10}$
$\:\lim_{x\to\:4}\frac{2-\sqrt{4x-12}}{x-4}\:$
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