$m+n+3m+-2n+10m$
$4-2t\ge t-5$
$\frac{b^2}{b}$
$4x^8-24x+36$
$\lim_{x\to\infty}\left(\frac{5e^{x-3}}{\ln\left(x-2\right)}\right)$
$a+6a+3$
$\frac{1}{\sin\left(a\right).\cos\left(b\right)}-\frac{\cos\left(b\right)}{\sin\left(a\right)}=\tan\left(c\right)$
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