$4x^3+6x^2-2x-2$
$\left(-2\right)^2-\left(-2\right)^3$
$\left(j-48\right)^2$
$5x-3>x+9$
$-\left(-81\right)+\left(-49\right)$
$\sqrt{9\cdot16}$
$\lim_{x\to0}\left(\frac{1-\cos2\left(x\right)}{\left(1-e^x\right)x}\right)$
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