$y',\:\frac{\sqrt{1-9x}\left(x^2+8\right)^2}{x^2+7x+2}$
$\int\frac{\cos^3\left(x\right)}{\sin^4\left(x\right)}dx$
$\int\frac{\left(x^2+4x-3\right)}{\left(x-3\right)\left(x^2+9\right)}dx$
$y^2+5y-25$
$\frac{\left(32-8x\right)}{4}$
$\log4n^3$
$3.45+9.69+8.72$
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