$\int_0^1\left(12e^{-4x}\right)dx$
$18-\left(2\cdot10^{-1}\right)$
$\int\frac{\left(8x+4\right)}{\sqrt{1-4x^2}}dx$
$\frac{d}{dx}y=x=45$
$7x^3-2x^3+4x+9\:$
$-\frac{1500}{30}$
$\frac{1}{x^{-2}}$
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