$y=4x^2+6x+1$
$\int y^3+1.8y^2-2.4y\:dy$
$\left(4xy^2+6\right)\left(4xy^2-\frac{3}{4}\right)$
$\lim_{x\to\infty}\:x+ln\:x$
$\left(\frac{3}{5}\:x\:-1\right)\left(\frac{3}{5}x\:+1\right)$
$4x-8<x-2$
$\left(3x^2-4z\right)^2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!