$\lim_{x\to4}\left(\frac{x^4-16}{x^2-8}\right)$
$x=12-y$
$\left(2xe^x-y+6x^2\right)dx-xdy=0$
$10+4h-8h-1$
$sin\left(4x\right)dx+2.y.cos^3\left(4x\right)dy=0$
$-2\left(s-6\right)=3\left(6-s\right)$
$0.9\cdot\left(1-\frac{1}{3^{0.08\cdot t}}\right)$
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