$\frac{d}{dx}x^3y^3+3x=2y+8$

$6z^2-12z$

$\left(t\cdot x'\right)+\left(2\cdot x\right)=5$

$-2\left(x+5\right)=-2\left(x-2\right)+5$

$0=cos\left(\frac{\pi}{6}x\right)$

$\lim_{x\to0}\left(\frac{4\left(1-\cos\left(x\right)\right)-2x^2}{x^2}\right)$

$x\ln9+x\ln12=x\ln16$