$\int\frac{x^3}{\sqrt{x^2-16x}}dx$

$\frac{2x}{3}+5x^9-3x^4$

$\frac{dy}{dx}=\frac{y^2}{x};\:y\left(1\right)=1$

$\left(\frac{-12}{6}\right)^2$

$\left(2^{-2}+1\right)^{3}$

$2-1\left\{5-4\left[6-7\left(2-9\right)+4\right]-8\right\}+3$

$\left(36x-1\right)\left(-5x+6\right)$