$\int x^3e^{ax}dx$
$7x-4<0$
$x+6>4-3x$
$xy'+5y=4x^7+6x^3$
$[\frac{\left(2x+1\right)^{3}}{\left(x-4\right)}]$
$64y^2b^4+34yb^2+16$
$\frac{dy}{dx}=\frac{4x+5y}{5x+9y}$
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