$x^3-4x^2-2x+8$

$\frac{1}{\cos\left(x\right)}-\frac{\cos\left(x\right)}{1+\sin}=-\sin\left(x\right)$

$x+\frac{4}{x}=1$

$\tan\left(x\right)\cos\left(x\right)-\tan\left(x\right)\csc\left(x\right)$

$3^3+6+2^4$

$\int\left(2\cdot\left(2x+6\right)^3\right)dx$

$y''+2y'-3y=0$