$\frac{x^4+x^2-x-2}{x^3-1}$
$a^2+6a=-5$
$y=\frac{3}{4}\tan^{-1}\left(x\right)$
$\left(3x^2+u^2\right)x'+2xy+3u^2$
$0.4330127018922193\cdot49$
$18:6-\left(7+4\right)-9-3-\left(5\cdot6\right)$
$f\left(x\right)=\frac{5x^3+7x}{2x^2-4x+5}$
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