$\left(4b^2+6c\right)^3$
$-18x\:\:\:=72$
$45-24-37+87-23+35$
$dx-e^{3x}dy=0$
$-x^2+3x+y=-10$
$\tan\left(2a\right)=\frac{2\:tana}{1-tan^2a}$
$\frac{dy}{dx}=\frac{x^2-1}{y+1}$
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