$4-3x\ge x+6$
$\frac{3x^4-4x^3+6x^3-5}{1-2x}$
$\int x\cos\left(3x^2\right)^{-1}dx$
$x^2+2x+6\le5$
$\frac{3}{x+1}=\frac{2}{x+3}$
$\frac{dx}{dy}=x^2-2x+2$
$2a^2+a=1$
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