$\int\left(\frac{1}{\sqrt{16-25x^2}}\right)dx$

$\int\frac{\left(x^2+3x\right)}{x-2}dx$

$\lim_{x\to\infty}\left(\frac{tan\left(4x\right)}{ln\left(1+x\right)}\right)$

$2x^23x-14$

$\left(2\left(1+\frac{x}{2}\right)\right)^{\frac{1}{3}}$

$8mn+24m^2-16y$

$\frac{x}{3}+\frac{y}{3}$