$\left(4v^0\right)^4$

$\left(-17\right)x\left(+8\right)$

$\lim_{x\to0}\left(\frac{\left(1+x\right)^n-1}{x}\:\right)$

$\left(5x+\text{4}\right)\left(5x-5\right)$

$v^2-16v+64$

$\lim_{x\to\infty}\left(\frac{\ln\left(x^4+1\right)}{x}\right)$

$\log\left(x-2\right)+\log\left(x+2\right)=\log\left(2\cdot x-1\right)$