$1\lim_{x\to-3}\left(2x^2+4x+1\right)$
$3x-2\left(x+1\right)+7\left(x+2\right)<\frac{x}{5}$
$g\left(x\right)=\:\:x+4\:\:-\:3\:$
$8xy-3x-3yx+2y$
$\frac{x\cdot\left[y+1\right]}{y};\:x=6;\:y=\:-2$
$\frac{1-256a^{10}}{1+16a^5}$
$-423+164$
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