$7x+5<2x-3$
$\lim_{x\to infinite}\left(11x^2\right)$
$\left(8a^5b-7x^2y^3\right)\left(8a^5b+7x^2y^3\right)$
$\frac{d}{dx}\left(\left(x+8\right)^3\left(5x-7\right)^5\right)$
$4177\cdot93$
$\frac{4}{8x^2}-1$
$\left(-4+17\right)\left(23-9\right)$
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