$2,5\:+\:18,75$
$\frac{x+3}{4}=6$
$12x<6x+12\:$
$3x^3+7\cdot x$
$8m^2+7m+9\cdot6m+3$
$\left(3a^5-2\right)\left(a^5+7\right)$
$4l+l^2+3l^4$
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